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121301410427 is a prime number
BaseRepresentation
bin111000011111000100…
…0001010001001111011
3102121002201000002222122
41300332020022021323
53441411130113202
6131420342111455
711522650655621
oct1607610121173
9377081002878
10121301410427
114749753602a
121b61371b58b
13b5919c7302
145c2a113511
15324e3739a2
hex1c3e20a27b

121301410427 has 2 divisors, whose sum is σ = 121301410428. Its totient is φ = 121301410426.

The previous prime is 121301410393. The next prime is 121301410429. The reversal of 121301410427 is 724014103121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121301410427 is a prime.

Together with 121301410429, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 121301410396 and 121301410405.

It is not a weakly prime, because it can be changed into another prime (121301410429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60650705213 + 60650705214.

It is an arithmetic number, because the mean of its divisors is an integer number (60650705214).

Almost surely, 2121301410427 is an apocalyptic number.

121301410427 is a deficient number, since it is larger than the sum of its proper divisors (1).

121301410427 is an equidigital number, since it uses as much as digits as its factorization.

121301410427 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 121301410427 its reverse (724014103121), we get a palindrome (845315513548).

The spelling of 121301410427 in words is "one hundred twenty-one billion, three hundred one million, four hundred ten thousand, four hundred twenty-seven".