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1213030310131 is a prime number
BaseRepresentation
bin10001101001101110001…
…111011010000011110011
311021222001011112110010101
4101221232033122003303
5124333241224411011
62325131453213231
7153432010340263
oct21515617320363
94258034473111
101213030310131
11428496a93a42
12177115491217
138a50803c8a3
14429d4d037a3
1521848b282c1
hex11a6e3da0f3

1213030310131 has 2 divisors, whose sum is σ = 1213030310132. Its totient is φ = 1213030310130.

The previous prime is 1213030310119. The next prime is 1213030310143. The reversal of 1213030310131 is 1310130303121.

It is a balanced prime because it is at equal distance from previous prime (1213030310119) and next prime (1213030310143).

It is an emirp because it is prime and its reverse (1310130303121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1213030310131 - 29 = 1213030309619 is a prime.

It is a super-2 number, since 2×12130303101312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1213030310099 and 1213030310108.

It is not a weakly prime, because it can be changed into another prime (1213030310161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606515155065 + 606515155066.

It is an arithmetic number, because the mean of its divisors is an integer number (606515155066).

Almost surely, 21213030310131 is an apocalyptic number.

1213030310131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213030310131 is an equidigital number, since it uses as much as digits as its factorization.

1213030310131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1213030310131 its reverse (1310130303121), we get a palindrome (2523160613252).

The spelling of 1213030310131 in words is "one trillion, two hundred thirteen billion, thirty million, three hundred ten thousand, one hundred thirty-one".