Base | Representation |
---|---|
bin | 1011000010000111100000… |
… | …0000110110110000111110 |
3 | 1120221201020022211020021120 |
4 | 2300201320000312300332 |
5 | 3042223242242243032 |
6 | 41444523251011410 |
7 | 2361302342203212 |
oct | 260417000666076 |
9 | 46851208736246 |
10 | 12131001134142 |
11 | 3957801981920 |
12 | 143b09b899b66 |
13 | 69cc43b0a887 |
14 | 2dd20200c942 |
15 | 16084dadb62c |
hex | b0878036c3e |
12131001134142 has 32 divisors (see below), whose sum is σ = 26467762988160. Its totient is φ = 3676043706720.
The previous prime is 12131001134093. The next prime is 12131001134149. The reversal of 12131001134142 is 24143110013121.
It is a super-2 number, since 2×121310011341422 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12131001134149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25244109 + ... + 25720167.
It is an arithmetic number, because the mean of its divisors is an integer number (827117593380).
Almost surely, 212131001134142 is an apocalyptic number.
12131001134142 is an abundant number, since it is smaller than the sum of its proper divisors (14336761854018).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12131001134142 is a wasteful number, since it uses less digits than its factorization.
12131001134142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 862168.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 12131001134142 its reverse (24143110013121), we get a palindrome (36274111147263).
The spelling of 12131001134142 in words is "twelve trillion, one hundred thirty-one billion, one million, one hundred thirty-four thousand, one hundred forty-two".
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