Base | Representation |
---|---|
bin | 10110100110001000… |
… | …00110110000011111 |
3 | 1011022102121211021002 |
4 | 23103010012300133 |
5 | 144321014102143 |
6 | 5323425300515 |
7 | 606421553630 |
oct | 132304066037 |
9 | 34272554232 |
10 | 12131003423 |
11 | 51656a9470 |
12 | 242679473b |
13 | 11b4341c46 |
14 | 83119d887 |
15 | 4aeeeb5b8 |
hex | 2d3106c1f |
12131003423 has 16 divisors (see below), whose sum is σ = 15180618240. Its totient is φ = 9417573600.
The previous prime is 12131003363. The next prime is 12131003431. The reversal of 12131003423 is 32430013121.
It is a cyclic number.
It is not a de Polignac number, because 12131003423 - 210 = 12131002399 is a prime.
It is a super-2 number, since 2×121310034232 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12131003395 and 12131003404.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12131003323) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 272123 + ... + 313548.
It is an arithmetic number, because the mean of its divisors is an integer number (948788640).
Almost surely, 212131003423 is an apocalyptic number.
12131003423 is a deficient number, since it is larger than the sum of its proper divisors (3049614817).
12131003423 is a wasteful number, since it uses less digits than its factorization.
12131003423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 585958.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 12131003423 its reverse (32430013121), we get a palindrome (44561016544).
The spelling of 12131003423 in words is "twelve billion, one hundred thirty-one million, three thousand, four hundred twenty-three".
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