Base | Representation |
---|---|
bin | 111000011111010100… |
… | …1010011111010000111 |
3 | 102121010022100122101102 |
4 | 1300332221103322013 |
5 | 3441420341214002 |
6 | 131421252250315 |
7 | 11523114563135 |
oct | 1607651237207 |
9 | 377108318342 |
10 | 121310101127 |
11 | 474a1431526 |
12 | 1b61661099b |
13 | b59374ac37 |
14 | 5c2b336755 |
15 | 324eedda02 |
hex | 1c3ea53e87 |
121310101127 has 2 divisors, whose sum is σ = 121310101128. Its totient is φ = 121310101126.
The previous prime is 121310100997. The next prime is 121310101153. The reversal of 121310101127 is 721101013121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121310101127 - 228 = 121041665671 is a prime.
It is a super-2 number, since 2×1213101011272 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121310101099 and 121310101108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121310104127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60655050563 + 60655050564.
It is an arithmetic number, because the mean of its divisors is an integer number (60655050564).
Almost surely, 2121310101127 is an apocalyptic number.
121310101127 is a deficient number, since it is larger than the sum of its proper divisors (1).
121310101127 is an equidigital number, since it uses as much as digits as its factorization.
121310101127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 121310101127 its reverse (721101013121), we get a palindrome (842411114248).
The spelling of 121310101127 in words is "one hundred twenty-one billion, three hundred ten million, one hundred one thousand, one hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •