Base | Representation |
---|---|
bin | 111000011111010100… |
… | …1010110000101101111 |
3 | 102121010022101002122101 |
4 | 1300332221112011233 |
5 | 3441420342010223 |
6 | 131421252355531 |
7 | 11523114631162 |
oct | 1607651260557 |
9 | 377108332571 |
10 | 121310110063 |
11 | 474a143820a |
12 | 1b616615ba7 |
13 | b59375201c |
14 | 5c2b339ad9 |
15 | 324eee14ad |
hex | 1c3ea5616f |
121310110063 has 2 divisors, whose sum is σ = 121310110064. Its totient is φ = 121310110062.
The previous prime is 121310110013. The next prime is 121310110079. The reversal of 121310110063 is 360011013121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121310110063 is a prime.
It is a super-2 number, since 2×1213101100632 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 121310110063.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121310110013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60655055031 + 60655055032.
It is an arithmetic number, because the mean of its divisors is an integer number (60655055032).
Almost surely, 2121310110063 is an apocalyptic number.
121310110063 is a deficient number, since it is larger than the sum of its proper divisors (1).
121310110063 is an equidigital number, since it uses as much as digits as its factorization.
121310110063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 121310110063 its reverse (360011013121), we get a palindrome (481321123184).
The spelling of 121310110063 in words is "one hundred twenty-one billion, three hundred ten million, one hundred ten thousand, sixty-three".
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