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121310134343623 is a prime number
BaseRepresentation
bin11011100101010010110111…
…011101110001011111000111
3120220112010122211200111002201
4123211102313131301133013
5111400021123342443443
61110001034550415331
734360240134312061
oct3345226735613707
9526463584614081
10121310134343623
11357203803197a5
1211732872661547
13528c65bcbb134
1421d562854c731
15e0584d12434d
hex6e54b77717c7

121310134343623 has 2 divisors, whose sum is σ = 121310134343624. Its totient is φ = 121310134343622.

The previous prime is 121310134343611. The next prime is 121310134343633. The reversal of 121310134343623 is 326343431013121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121310134343623 - 217 = 121310134212551 is a prime.

It is a super-2 number, since 2×1213101343436232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121310134343603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60655067171811 + 60655067171812.

It is an arithmetic number, because the mean of its divisors is an integer number (60655067171812).

Almost surely, 2121310134343623 is an apocalyptic number.

121310134343623 is a deficient number, since it is larger than the sum of its proper divisors (1).

121310134343623 is an equidigital number, since it uses as much as digits as its factorization.

121310134343623 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 37.

Adding to 121310134343623 its reverse (326343431013121), we get a palindrome (447653565356744).

The spelling of 121310134343623 in words is "one hundred twenty-one trillion, three hundred ten billion, one hundred thirty-four million, three hundred forty-three thousand, six hundred twenty-three".