Base | Representation |
---|---|
bin | 10001101001110011000… |
… | …111001010000000101011 |
3 | 11021222020212022102021021 |
4 | 101221303013022000223 |
5 | 124333423140031243 |
6 | 2325143532553311 |
7 | 153434022101311 |
oct | 21516307120053 |
9 | 4258225272237 |
10 | 1213112033323 |
11 | 428529131873 |
12 | 177138922837 |
13 | 8a51bc543c8 |
14 | 42a01ad80b1 |
15 | 21850dbc6ed |
hex | 11a731ca02b |
1213112033323 has 2 divisors, whose sum is σ = 1213112033324. Its totient is φ = 1213112033322.
The previous prime is 1213112033321. The next prime is 1213112033333. The reversal of 1213112033323 is 3233302113121.
It is a weak prime.
It is an emirp because it is prime and its reverse (3233302113121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1213112033323 - 21 = 1213112033321 is a prime.
Together with 1213112033321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1213112033321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606556016661 + 606556016662.
It is an arithmetic number, because the mean of its divisors is an integer number (606556016662).
Almost surely, 21213112033323 is an apocalyptic number.
1213112033323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213112033323 is an equidigital number, since it uses as much as digits as its factorization.
1213112033323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1213112033323 its reverse (3233302113121), we get a palindrome (4446414146444).
The spelling of 1213112033323 in words is "one trillion, two hundred thirteen billion, one hundred twelve million, thirty-three thousand, three hundred twenty-three".
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