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12131220524147 is a prime number
BaseRepresentation
bin1011000010001000010100…
…0101110000110001110011
31120221201210121122101210022
42300202011011300301303
53042224214423233042
641445001125154055
72361310645036214
oct260420505606163
946851717571708
1012131220524147
1139579047a887a
12143b14125b92b
1369cc7a3c374a
142dd2231db40b
15160862ec5cd2
hexb0885170c73

12131220524147 has 2 divisors, whose sum is σ = 12131220524148. Its totient is φ = 12131220524146.

The previous prime is 12131220524069. The next prime is 12131220524167. The reversal of 12131220524147 is 74142502213121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12131220524147 - 224 = 12131203746931 is a prime.

It is a super-2 number, since 2×121312205241472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12131220524167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065610262073 + 6065610262074.

It is an arithmetic number, because the mean of its divisors is an integer number (6065610262074).

Almost surely, 212131220524147 is an apocalyptic number.

12131220524147 is a deficient number, since it is larger than the sum of its proper divisors (1).

12131220524147 is an equidigital number, since it uses as much as digits as its factorization.

12131220524147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 35.

Adding to 12131220524147 its reverse (74142502213121), we get a palindrome (86273722737268).

The spelling of 12131220524147 in words is "twelve trillion, one hundred thirty-one billion, two hundred twenty million, five hundred twenty-four thousand, one hundred forty-seven".