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12131220524167 is a prime number
BaseRepresentation
bin1011000010001000010100…
…0101110000110010000111
31120221201210121122101211001
42300202011011300302013
53042224214423233132
641445001125154131
72361310645036243
oct260420505606207
946851717571731
1012131220524167
1139579047a8898
12143b14125b947
1369cc7a3c3764
142dd2231db423
15160862ec5ce7
hexb0885170c87

12131220524167 has 2 divisors, whose sum is σ = 12131220524168. Its totient is φ = 12131220524166.

The previous prime is 12131220524147. The next prime is 12131220524173. The reversal of 12131220524167 is 76142502213121.

It is a strong prime.

It is an emirp because it is prime and its reverse (76142502213121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12131220524167 - 231 = 12129073040519 is a prime.

It is a super-2 number, since 2×121312205241672 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12131220524147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065610262083 + 6065610262084.

It is an arithmetic number, because the mean of its divisors is an integer number (6065610262084).

Almost surely, 212131220524167 is an apocalyptic number.

12131220524167 is a deficient number, since it is larger than the sum of its proper divisors (1).

12131220524167 is an equidigital number, since it uses as much as digits as its factorization.

12131220524167 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40320, while the sum is 37.

Adding to 12131220524167 its reverse (76142502213121), we get a palindrome (88273722737288).

The spelling of 12131220524167 in words is "twelve trillion, one hundred thirty-one billion, two hundred twenty million, five hundred twenty-four thousand, one hundred sixty-seven".