Base | Representation |
---|---|
bin | 100100001001110… |
… | …1100110111010011 |
3 | 10010112201002100102 |
4 | 1020103230313103 |
5 | 4441024432201 |
6 | 320213243015 |
7 | 42030245546 |
oct | 11023546723 |
9 | 3115632312 |
10 | 1213124051 |
11 | 572860067 |
12 | 29a33346b |
13 | 16443aca9 |
14 | b718885d |
15 | 7177e26b |
hex | 484ecdd3 |
1213124051 has 2 divisors, whose sum is σ = 1213124052. Its totient is φ = 1213124050.
The previous prime is 1213124021. The next prime is 1213124071. The reversal of 1213124051 is 1504213121.
It is an a-pointer prime, because the next prime (1213124071) can be obtained adding 1213124051 to its sum of digits (20).
It is a strong prime.
It is an emirp because it is prime and its reverse (1504213121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1213124051 - 210 = 1213123027 is a prime.
It is a super-2 number, since 2×12131240512 = 2943339926229301202, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1213124021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606562025 + 606562026.
It is an arithmetic number, because the mean of its divisors is an integer number (606562026).
Almost surely, 21213124051 is an apocalyptic number.
1213124051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213124051 is an equidigital number, since it uses as much as digits as its factorization.
1213124051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 20.
The square root of 1213124051 is about 34829.9303903984. The cubic root of 1213124051 is about 1066.5185273548.
Adding to 1213124051 its reverse (1504213121), we get a palindrome (2717337172).
The spelling of 1213124051 in words is "one billion, two hundred thirteen million, one hundred twenty-four thousand, fifty-one".
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