Base | Representation |
---|---|
bin | 1011000010001000101010… |
… | …0000000010111000000111 |
3 | 1120221202000221110021222202 |
4 | 2300202022200002320013 |
5 | 3042224411143100403 |
6 | 41445014130545115 |
7 | 2361313126443152 |
oct | 260421240027007 |
9 | 46852027407882 |
10 | 12131311300103 |
11 | 3957950a6a126 |
12 | 143b16773819b |
13 | 69cc93157928 |
14 | 2dd2312aac99 |
15 | 16086ae57688 |
hex | b088a802e07 |
12131311300103 has 8 divisors (see below), whose sum is σ = 12220524352848. Its totient is φ = 12042107861184.
The previous prime is 12131311300093. The next prime is 12131311300109. The reversal of 12131311300103 is 30100311313121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12131311300103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12131311300109) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 139400 + ... + 4927682.
It is an arithmetic number, because the mean of its divisors is an integer number (1527565544106).
Almost surely, 212131311300103 is an apocalyptic number.
12131311300103 is a deficient number, since it is larger than the sum of its proper divisors (89213052745).
12131311300103 is a wasteful number, since it uses less digits than its factorization.
12131311300103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4806913.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 12131311300103 its reverse (30100311313121), we get a palindrome (42231622613224).
The spelling of 12131311300103 in words is "twelve trillion, one hundred thirty-one billion, three hundred eleven million, three hundred thousand, one hundred three".
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