Base | Representation |
---|---|
bin | 11011100101010101110110… |
… | …000111101101111010001011 |
3 | 120220112102220202112120112222 |
4 | 123211111312013231322023 |
5 | 111400044201222310214 |
6 | 1110002324213124255 |
7 | 34360412324446151 |
oct | 3345256607557213 |
9 | 526472822476488 |
10 | 121313333010059 |
11 | 35721771941183 |
12 | 1173340592968b |
13 | 528ca4b8b0978 |
14 | 21d584d2ab3d1 |
15 | e05988d5c38e |
hex | 6e55761ede8b |
121313333010059 has 2 divisors, whose sum is σ = 121313333010060. Its totient is φ = 121313333010058.
The previous prime is 121313333010007. The next prime is 121313333010061. The reversal of 121313333010059 is 950010333313121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121313333010059 - 244 = 103721146965643 is a prime.
Together with 121313333010061, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (121313333010959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60656666505029 + 60656666505030.
It is an arithmetic number, because the mean of its divisors is an integer number (60656666505030).
Almost surely, 2121313333010059 is an apocalyptic number.
121313333010059 is a deficient number, since it is larger than the sum of its proper divisors (1).
121313333010059 is an equidigital number, since it uses as much as digits as its factorization.
121313333010059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21870, while the sum is 35.
The spelling of 121313333010059 in words is "one hundred twenty-one trillion, three hundred thirteen billion, three hundred thirty-three million, ten thousand, fifty-nine".
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