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1213141110334 = 2606570555167
BaseRepresentation
bin10001101001110100110…
…110000100111000111110
311021222022220000200102121
4101221310312010320332
5124334003111012314
62325150452113154
7153434524204036
oct21516466047076
94258286020377
101213141110334
1142854359185a
121771466057ba
138a524c9523a
1442a059068c6
1521853712d24
hex11a74d84e3e

1213141110334 has 4 divisors (see below), whose sum is σ = 1819711665504. Its totient is φ = 606570555166.

The previous prime is 1213141110319. The next prime is 1213141110347. The reversal of 1213141110334 is 4330111413121.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×12131411103342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1213141110299 and 1213141110308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 303285277582 + ... + 303285277585.

It is an arithmetic number, because the mean of its divisors is an integer number (454927916376).

Almost surely, 21213141110334 is an apocalyptic number.

1213141110334 is a deficient number, since it is larger than the sum of its proper divisors (606570555170).

1213141110334 is an equidigital number, since it uses as much as digits as its factorization.

1213141110334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 606570555169.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1213141110334 its reverse (4330111413121), we get a palindrome (5543252523455).

The spelling of 1213141110334 in words is "one trillion, two hundred thirteen billion, one hundred forty-one million, one hundred ten thousand, three hundred thirty-four".

Divisors: 1 2 606570555167 1213141110334