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12131422412597 is a prime number
BaseRepresentation
bin1011000010001001000100…
…0111111001111100110101
31120221202022200112101200022
42300202101013321330311
53042230123114200342
641445033140254525
72361315646050245
oct260422107717465
946852280471608
1012131422412597
1139579a8760634
12143b1989a1445
1369ccb018c477
142dd241d51b25
15160875aa49d2
hexb08911f9f35

12131422412597 has 2 divisors, whose sum is σ = 12131422412598. Its totient is φ = 12131422412596.

The previous prime is 12131422412573. The next prime is 12131422412687. The reversal of 12131422412597 is 79521422413121.

12131422412597 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7356712330276 + 4774710082321 = 2712326^2 + 2185111^2 .

It is a cyclic number.

It is not a de Polignac number, because 12131422412597 - 214 = 12131422396213 is a prime.

It is a super-2 number, since 2×121314224125972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12131422412507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065711206298 + 6065711206299.

It is an arithmetic number, because the mean of its divisors is an integer number (6065711206299).

Almost surely, 212131422412597 is an apocalyptic number.

It is an amenable number.

12131422412597 is a deficient number, since it is larger than the sum of its proper divisors (1).

12131422412597 is an equidigital number, since it uses as much as digits as its factorization.

12131422412597 is an evil number, because the sum of its binary digits is even.

The product of its digits is 241920, while the sum is 44.

The spelling of 12131422412597 in words is "twelve trillion, one hundred thirty-one billion, four hundred twenty-two million, four hundred twelve thousand, five hundred ninety-seven".