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1213142405243 = 10112011310943
BaseRepresentation
bin10001101001110100111…
…011000001000001111011
311021222022222110110201012
4101221310323001001323
5124334003423431433
62325150535544135
7153434541206216
oct21516473010173
94258288413635
101213142405243
1142854429672a
12177146b2b04b
138a525329762
1442a05b6277d
15218538bb848
hex11a74ec107b

1213142405243 has 4 divisors (see below), whose sum is σ = 1225153716288. Its totient is φ = 1201131094200.

The previous prime is 1213142405219. The next prime is 1213142405309. The reversal of 1213142405243 is 3425042413121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1213142405243 - 210 = 1213142404219 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1213142405443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6005655371 + ... + 6005655572.

It is an arithmetic number, because the mean of its divisors is an integer number (306288429072).

Almost surely, 21213142405243 is an apocalyptic number.

1213142405243 is a deficient number, since it is larger than the sum of its proper divisors (12011311045).

1213142405243 is a wasteful number, since it uses less digits than its factorization.

1213142405243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12011311044.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 1213142405243 its reverse (3425042413121), we get a palindrome (4638184818364).

The spelling of 1213142405243 in words is "one trillion, two hundred thirteen billion, one hundred forty-two million, four hundred five thousand, two hundred forty-three".

Divisors: 1 101 12011310943 1213142405243