1213204013132 has 12 divisors (see below), whose sum is σ = 2123388617616. Its totient is φ = 606521550960.

The previous prime is 1213204013111. The next prime is 1213204013191. The reversal of 1213204013132 is 2313104023121.

It is a junction number, because it is equal to n+sod(n) for n = 1213204013098 and 1213204013107.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20079968 + ... + 20140295.

It is an arithmetic number, because the mean of its divisors is an integer number (176949051468).

Almost surely, 2^{1213204013132} is an apocalyptic number.

It is an amenable number.

1213204013132 is a deficient number, since it is larger than the sum of its proper divisors (910184604484).

1213204013132 is a wasteful number, since it uses less digits than its factorization.

1213204013132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40227808 (or 40227806 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1213204013132 its reverse (2313104023121), we get a palindrome (3526308036253).

The spelling of 1213204013132 in words is "one trillion, two hundred thirteen billion, two hundred four million, thirteen thousand, one hundred thirty-two".