Base | Representation |
---|---|
bin | 111000011111101001… |
… | …1010110110100101101 |
3 | 102121011002002121201021 |
4 | 1300333103112310231 |
5 | 3441431201414432 |
6 | 131422324414141 |
7 | 11523310350205 |
oct | 1607723266455 |
9 | 377132077637 |
10 | 121321123117 |
11 | 474a767a507 |
12 | 1b61a247351 |
13 | b595b09a1c |
14 | 5c2c9a5405 |
15 | 3250e69697 |
hex | 1c3f4d6d2d |
121321123117 has 2 divisors, whose sum is σ = 121321123118. Its totient is φ = 121321123116.
The previous prime is 121321123109. The next prime is 121321123129. The reversal of 121321123117 is 711321123121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 112443526276 + 8877596841 = 335326^2 + 94221^2 .
It is a cyclic number.
It is not a de Polignac number, because 121321123117 - 23 = 121321123109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121321123091 and 121321123100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121321123177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60660561558 + 60660561559.
It is an arithmetic number, because the mean of its divisors is an integer number (60660561559).
Almost surely, 2121321123117 is an apocalyptic number.
It is an amenable number.
121321123117 is a deficient number, since it is larger than the sum of its proper divisors (1).
121321123117 is an equidigital number, since it uses as much as digits as its factorization.
121321123117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 504, while the sum is 25.
Adding to 121321123117 its reverse (711321123121), we get a palindrome (832642246238).
The spelling of 121321123117 in words is "one hundred twenty-one billion, three hundred twenty-one million, one hundred twenty-three thousand, one hundred seventeen".
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