12132130433 has 4 divisors (see below), whose sum is σ = 12150051540. Its totient is φ = 12114209328.

The previous prime is 12132130399. The next prime is 12132130469. The reversal of 12132130433 is 33403123121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12027947584 + 104182849 = 109672^2 + 10207^2 .

It is a cyclic number.

It is not a de Polignac number, because 12132130433 - 2¹⁸ = 12131868289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12132130399 and 12132130408.

It is not an unprimeable number, because it can be changed into a prime (12132130033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8959538 + ... + 8960891.

It is an arithmetic number, because the mean of its divisors is an integer number (3037512885).

Almost surely, 2^12132130433 is an apocalyptic number.

It is an amenable number.

12132130433 is a deficient number, since it is larger than the sum of its proper divisors (17921107).

12132130433 is an equidigital number, since it uses as much as digits as its factorization.

12132130433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17921106.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 12132130433 its reverse (33403123121), we get a palindrome (45535253554).

The spelling of 12132130433 in words is "twelve billion, one hundred thirty-two million, one hundred thirty thousand, four hundred thirty-three".