Base | Representation |
---|---|
bin | 10110100110010011… |
… | …00101110100111001 |
3 | 1011022112022212210112 |
4 | 23103021211310321 |
5 | 144321401111101 |
6 | 5323520154105 |
7 | 606440023163 |
oct | 132311456471 |
9 | 34275285715 |
10 | 12132441401 |
11 | 51664a0883 |
12 | 2427168935 |
13 | 11b4726612 |
14 | 831455933 |
15 | 4b01d26bb |
hex | 2d3265d39 |
12132441401 has 2 divisors, whose sum is σ = 12132441402. Its totient is φ = 12132441400.
The previous prime is 12132441359. The next prime is 12132441427. The reversal of 12132441401 is 10414423121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10951831801 + 1180609600 = 104651^2 + 34360^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12132441401 is a prime.
It is a super-2 number, since 2×121324414012 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12132441001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066220700 + 6066220701.
It is an arithmetic number, because the mean of its divisors is an integer number (6066220701).
Almost surely, 212132441401 is an apocalyptic number.
It is an amenable number.
12132441401 is a deficient number, since it is larger than the sum of its proper divisors (1).
12132441401 is an equidigital number, since it uses as much as digits as its factorization.
12132441401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 12132441401 its reverse (10414423121), we get a palindrome (22546864522).
The spelling of 12132441401 in words is "twelve billion, one hundred thirty-two million, four hundred forty-one thousand, four hundred one".
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