Base | Representation |
---|---|
bin | 111000011111110001… |
… | …1011101100100010111 |
3 | 102121011101001010010001 |
4 | 1300333203131210113 |
5 | 3441433242020142 |
6 | 131422555112131 |
7 | 11523361263064 |
oct | 1607743354427 |
9 | 377141033101 |
10 | 121325345047 |
11 | 474a9aa3505 |
12 | 1b61b742647 |
13 | b5969575ca |
14 | 5c2d383c6b |
15 | 32515005b7 |
hex | 1c3f8dd917 |
121325345047 has 2 divisors, whose sum is σ = 121325345048. Its totient is φ = 121325345046.
The previous prime is 121325345033. The next prime is 121325345093. The reversal of 121325345047 is 740543523121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121325345047 - 215 = 121325312279 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121325344997 and 121325345015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121325345147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60662672523 + 60662672524.
It is an arithmetic number, because the mean of its divisors is an integer number (60662672524).
Almost surely, 2121325345047 is an apocalyptic number.
121325345047 is a deficient number, since it is larger than the sum of its proper divisors (1).
121325345047 is an equidigital number, since it uses as much as digits as its factorization.
121325345047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 37.
Adding to 121325345047 its reverse (740543523121), we get a palindrome (861868868168).
The spelling of 121325345047 in words is "one hundred twenty-one billion, three hundred twenty-five million, three hundred forty-five thousand, forty-seven".
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