12132540131 has 2 divisors, whose sum is σ = 12132540132. Its totient is φ = 12132540130.

The previous prime is 12132540109. The next prime is 12132540149. The reversal of 12132540131 is 13104523121.

It is a strong prime.

It is an emirp because it is prime and its reverse (13104523121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12132540131 is a prime.

It is a super-2 number, since 2×12132540131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12132540097 and 12132540106.

It is not a weakly prime, because it can be changed into another prime (12132540031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066270065 + 6066270066.

It is an arithmetic number, because the mean of its divisors is an integer number (6066270066).

Almost surely, 2^12132540131 is an apocalyptic number.

12132540131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12132540131 is an equidigital number, since it uses as much as digits as its factorization.

12132540131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

The spelling of 12132540131 in words is "twelve billion, one hundred thirty-two million, five hundred forty thousand, one hundred thirty-one".