Base | Representation |
---|---|
bin | 1011000010001110111111… |
… | …0101100010101011110110 |
3 | 1120221220102102120001120101 |
4 | 2300203233311202223312 |
5 | 3042241401411343410 |
6 | 41445454542424314 |
7 | 2361403222364341 |
oct | 260435765425366 |
9 | 46856372501511 |
10 | 12133011434230 |
11 | 3958643714055 |
12 | 143b560b9209a |
13 | 6a01a445025b |
14 | 2dd352dc9458 |
15 | 16091a335d3a |
hex | b08efd62af6 |
12133011434230 has 32 divisors (see below), whose sum is σ = 23523488524800. Its totient is φ = 4490847803232.
The previous prime is 12133011434207. The next prime is 12133011434293. The reversal of 12133011434230 is 3243411033121.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 742526190 + ... + 742542529.
It is an arithmetic number, because the mean of its divisors is an integer number (735109016400).
Almost surely, 212133011434230 is an apocalyptic number.
12133011434230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12133011434230 is a deficient number, since it is larger than the sum of its proper divisors (11390477090570).
12133011434230 is a wasteful number, since it uses less digits than its factorization.
12133011434230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1485068788.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 12133011434230 its reverse (3243411033121), we get a palindrome (15376422467351).
The spelling of 12133011434230 in words is "twelve trillion, one hundred thirty-three billion, eleven million, four hundred thirty-four thousand, two hundred thirty".
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