121330150035 has 8 divisors (see below), whose sum is σ = 194128240080. Its totient is φ = 64709413344.

The previous prime is 121330150009. The next prime is 121330150037. The reversal of 121330150035 is 530051033121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 121330150035 - 2¹⁰ = 121330149011 is a prime.

It is a super-2 number, since 2×121330150035² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121330149987 and 121330150014.

It is not an unprimeable number, because it can be changed into a prime (121330150037) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4044338320 + ... + 4044338349.

It is an arithmetic number, because the mean of its divisors is an integer number (24266030010).

Almost surely, 2^121330150035 is an apocalyptic number.

121330150035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

121330150035 is a deficient number, since it is larger than the sum of its proper divisors (72798090045).

121330150035 is an equidigital number, since it uses as much as digits as its factorization.

121330150035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8088676677.

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 121330150035 its reverse (530051033121), we get a palindrome (651381183156).

The spelling of 121330150035 in words is "one hundred twenty-one billion, three hundred thirty million, one hundred fifty thousand, thirty-five".