12133030113133 has 4 divisors (see below), whose sum is σ = 12133059790140. Its totient is φ = 12133000436128.

The previous prime is 12133030113101. The next prime is 12133030113137. The reversal of 12133030113133 is 33131103033121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6719692664169 + 5413337448964 = 2592237^2 + 2326658^2 .

It is a cyclic number.

It is not a de Polignac number, because 12133030113133 - 2⁵ = 12133030113101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12133030113098 and 12133030113107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12133030113137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14216560 + ... + 15045817.

It is an arithmetic number, because the mean of its divisors is an integer number (3033264947535).

Almost surely, 2^{12133030113133} is an apocalyptic number.

It is an amenable number.

12133030113133 is a deficient number, since it is larger than the sum of its proper divisors (29677007).

12133030113133 is an equidigital number, since it uses as much as digits as its factorization.

12133030113133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29677006.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 12133030113133 its reverse (33131103033121), we get a palindrome (45264133146254).

The spelling of 12133030113133 in words is "twelve trillion, one hundred thirty-three billion, thirty million, one hundred thirteen thousand, one hundred thirty-three".