Base | Representation |
---|---|
bin | 1011000010001111000110… |
… | …1111001011110111000110 |
3 | 1120221220111122120010210101 |
4 | 2300203301233023313012 |
5 | 3042241433042303220 |
6 | 41445502042114314 |
7 | 2361404060415451 |
oct | 260436157136706 |
9 | 46856448503711 |
10 | 12133043322310 |
11 | 395865a714039 |
12 | 143b56b7ab99a |
13 | 6a01aac36741 |
14 | 2dd35732a498 |
15 | 16091d03430a |
hex | b08f1bcbdc6 |
12133043322310 has 64 divisors (see below), whose sum is σ = 23551243128000. Its totient is φ = 4485336422400.
The previous prime is 12133043322247. The next prime is 12133043322311. The reversal of 12133043322310 is 1322334033121.
It is a super-2 number, since 2×121330433223102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12133043322311) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 135883080 + ... + 135972340.
It is an arithmetic number, because the mean of its divisors is an integer number (367988173875).
Almost surely, 212133043322310 is an apocalyptic number.
12133043322310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12133043322310 is a deficient number, since it is larger than the sum of its proper divisors (11418199805690).
12133043322310 is a wasteful number, since it uses less digits than its factorization.
12133043322310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106777.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 12133043322310 its reverse (1322334033121), we get a palindrome (13455377355431).
The spelling of 12133043322310 in words is "twelve trillion, one hundred thirty-three billion, forty-three million, three hundred twenty-two thousand, three hundred ten".
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