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1213310252131 is a prime number
BaseRepresentation
bin10001101001111110111…
…011010011010001100011
311021222202200021222100121
4101221332323103101203
5124334324411032011
62325215333301111
7153441646656565
oct21517673232143
94258680258317
101213310252131
1142862000856a
12177193194797
138a551036a43
1442a20175335
15218634c3e71
hex11a7eed3463

1213310252131 has 2 divisors, whose sum is σ = 1213310252132. Its totient is φ = 1213310252130.

The previous prime is 1213310252107. The next prime is 1213310252159. The reversal of 1213310252131 is 1312520133121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1213310252131 - 219 = 1213309727843 is a prime.

It is a super-3 number, since 3×12133102521313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1213310252096 and 1213310252105.

It is not a weakly prime, because it can be changed into another prime (1213310252101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606655126065 + 606655126066.

It is an arithmetic number, because the mean of its divisors is an integer number (606655126066).

Almost surely, 21213310252131 is an apocalyptic number.

1213310252131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213310252131 is an equidigital number, since it uses as much as digits as its factorization.

1213310252131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 1213310252131 its reverse (1312520133121), we get a palindrome (2525830385252).

The spelling of 1213310252131 in words is "one trillion, two hundred thirteen billion, three hundred ten million, two hundred fifty-two thousand, one hundred thirty-one".