Base | Representation |
---|---|
bin | 1011000010001111010101… |
… | …0011001110010001001001 |
3 | 1120221220122211001012201222 |
4 | 2300203311103032101021 |
5 | 3042242043343213001 |
6 | 41445512015251425 |
7 | 2361405414501401 |
oct | 260436523162111 |
9 | 46856584035658 |
10 | 12133103101001 |
11 | 3958690433713 |
12 | 143b587819b75 |
13 | 6a01ba436a4c |
14 | 2dd36124b801 |
15 | 1609233e161b |
hex | b08f54ce449 |
12133103101001 has 4 divisors (see below), whose sum is σ = 12133251750672. Its totient is φ = 12132954451332.
The previous prime is 12133103100997. The next prime is 12133103101033. The reversal of 12133103101001 is 10010130133121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12133103101001 - 22 = 12133103100997 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12133103101051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74202335 + ... + 74365668.
It is an arithmetic number, because the mean of its divisors is an integer number (3033312937668).
Almost surely, 212133103101001 is an apocalyptic number.
It is an amenable number.
12133103101001 is a deficient number, since it is larger than the sum of its proper divisors (148649671).
12133103101001 is an equidigital number, since it uses as much as digits as its factorization.
12133103101001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 148649670.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 12133103101001 its reverse (10010130133121), we get a palindrome (22143233234122).
The spelling of 12133103101001 in words is "twelve trillion, one hundred thirty-three billion, one hundred three million, one hundred one thousand, one".
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