Base | Representation |
---|---|
bin | 10110100110011000… |
… | …10000111010000101 |
3 | 1011022120122111001011 |
4 | 23103030100322011 |
5 | 144322041022044 |
6 | 5323543202221 |
7 | 606446002162 |
oct | 132314207205 |
9 | 34276574034 |
10 | 12133142149 |
11 | 516692a307 |
12 | 2427446371 |
13 | 11b491056b |
14 | 831599069 |
15 | 4b02c0134 |
hex | 2d3310e85 |
12133142149 has 2 divisors, whose sum is σ = 12133142150. Its totient is φ = 12133142148.
The previous prime is 12133142117. The next prime is 12133142159. The reversal of 12133142149 is 94124133121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11120757025 + 1012385124 = 105455^2 + 31818^2 .
It is a cyclic number.
It is not a de Polignac number, because 12133142149 - 25 = 12133142117 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12133142149.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12133142159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066571074 + 6066571075.
It is an arithmetic number, because the mean of its divisors is an integer number (6066571075).
Almost surely, 212133142149 is an apocalyptic number.
It is an amenable number.
12133142149 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133142149 is an equidigital number, since it uses as much as digits as its factorization.
12133142149 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 31.
The spelling of 12133142149 in words is "twelve billion, one hundred thirty-three million, one hundred forty-two thousand, one hundred forty-nine".
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