Base | Representation |
---|---|
bin | 11011100101100111100000… |
… | …111001111111001011110111 |
3 | 120220121020212220122011211020 |
4 | 123211213200321333023313 |
5 | 111400402024414121403 |
6 | 1110015142520512223 |
7 | 34361653420116516 |
oct | 3345474071771367 |
9 | 526536786564736 |
10 | 121332304442103 |
11 | 35729817804937 |
12 | 1173701b31b673 |
13 | 52917831581c1 |
14 | 21d672cb2a67d |
15 | e061e9652453 |
hex | 6e59e0e7f2f7 |
121332304442103 has 4 divisors (see below), whose sum is σ = 161776405922808. Its totient is φ = 80888202961400.
The previous prime is 121332304442093. The next prime is 121332304442117. The reversal of 121332304442103 is 301244403233121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 121332304442103 - 213 = 121332304433911 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121332304442183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20222050740348 + ... + 20222050740353.
It is an arithmetic number, because the mean of its divisors is an integer number (40444101480702).
Almost surely, 2121332304442103 is an apocalyptic number.
121332304442103 is a deficient number, since it is larger than the sum of its proper divisors (40444101480705).
121332304442103 is an equidigital number, since it uses as much as digits as its factorization.
121332304442103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40444101480704.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 121332304442103 its reverse (301244403233121), we get a palindrome (422576707675224).
The spelling of 121332304442103 in words is "one hundred twenty-one trillion, three hundred thirty-two billion, three hundred four million, four hundred forty-two thousand, one hundred three".
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