Base | Representation |
---|---|
bin | 1011000010010000000100… |
… | …1110010001111101100001 |
3 | 1120221221011202102211200112 |
4 | 2300210001032101331201 |
5 | 3042243001100211001 |
6 | 41445543522501105 |
7 | 2361413363645222 |
oct | 260440116217541 |
9 | 46857152384615 |
10 | 12133303132001 |
11 | 3958783337997 |
12 | 143b622804795 |
13 | 6a021ca0219c |
14 | 2dd37da3b249 |
15 | 160935c54cbb |
hex | b0901391f61 |
12133303132001 has 2 divisors, whose sum is σ = 12133303132002. Its totient is φ = 12133303132000.
The previous prime is 12133303131953. The next prime is 12133303132019. The reversal of 12133303132001 is 10023130333121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11242280408401 + 891022723600 = 3352951^2 + 943940^2 .
It is a cyclic number.
It is not a de Polignac number, because 12133303132001 - 214 = 12133303115617 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (12133303132021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066651566000 + 6066651566001.
It is an arithmetic number, because the mean of its divisors is an integer number (6066651566001).
Almost surely, 212133303132001 is an apocalyptic number.
It is an amenable number.
12133303132001 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133303132001 is an equidigital number, since it uses as much as digits as its factorization.
12133303132001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 12133303132001 its reverse (10023130333121), we get a palindrome (22156433465122).
The spelling of 12133303132001 in words is "twelve trillion, one hundred thirty-three billion, three hundred three million, one hundred thirty-two thousand, one".
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