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12133303201303 = 14657827816279
BaseRepresentation
bin1011000010010000000100…
…1110100010111000010111
31120221221011202120100202021
42300210001032202320113
53042243001104420203
641445543524154011
72361413364354244
oct260440116427027
946857152510667
1012133303201303
113958783384a69
12143b622838907
136a021ca278ab
142dd37da585cb
15160935c6a5bd
hexb09013a2e17

12133303201303 has 4 divisors (see below), whose sum is σ = 12134131032240. Its totient is φ = 12132475370368.

The previous prime is 12133303201301. The next prime is 12133303201307. The reversal of 12133303201303 is 30310230333121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12133303201303 - 21 = 12133303201301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12133303201301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 413893483 + ... + 413922796.

It is an arithmetic number, because the mean of its divisors is an integer number (3033532758060).

Almost surely, 212133303201303 is an apocalyptic number.

12133303201303 is a deficient number, since it is larger than the sum of its proper divisors (827830937).

12133303201303 is an equidigital number, since it uses as much as digits as its factorization.

12133303201303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 827830936.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 12133303201303 its reverse (30310230333121), we get a palindrome (42443533534424).

The spelling of 12133303201303 in words is "twelve trillion, one hundred thirty-three billion, three hundred three million, two hundred one thousand, three hundred three".

Divisors: 1 14657 827816279 12133303201303