Base | Representation |
---|---|
bin | 1011000010010000000100… |
… | …1110100010111000010111 |
3 | 1120221221011202120100202021 |
4 | 2300210001032202320113 |
5 | 3042243001104420203 |
6 | 41445543524154011 |
7 | 2361413364354244 |
oct | 260440116427027 |
9 | 46857152510667 |
10 | 12133303201303 |
11 | 3958783384a69 |
12 | 143b622838907 |
13 | 6a021ca278ab |
14 | 2dd37da585cb |
15 | 160935c6a5bd |
hex | b09013a2e17 |
12133303201303 has 4 divisors (see below), whose sum is σ = 12134131032240. Its totient is φ = 12132475370368.
The previous prime is 12133303201301. The next prime is 12133303201307. The reversal of 12133303201303 is 30310230333121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12133303201303 - 21 = 12133303201301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12133303201301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 413893483 + ... + 413922796.
It is an arithmetic number, because the mean of its divisors is an integer number (3033532758060).
Almost surely, 212133303201303 is an apocalyptic number.
12133303201303 is a deficient number, since it is larger than the sum of its proper divisors (827830937).
12133303201303 is an equidigital number, since it uses as much as digits as its factorization.
12133303201303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 827830936.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 12133303201303 its reverse (30310230333121), we get a palindrome (42443533534424).
The spelling of 12133303201303 in words is "twelve trillion, one hundred thirty-three billion, three hundred three million, two hundred one thousand, three hundred three".
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