12133343614540 has 24 divisors (see below), whose sum is σ = 25504687676160. Its totient is φ = 4848639143808.

The previous prime is 12133343614477. The next prime is 12133343614559. The reversal of 12133343614540 is 4541634333121.

It is a super-3 number, since 3×12133343614540³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12133343614493 and 12133343614502.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 293622700 + ... + 293664019.

It is an arithmetic number, because the mean of its divisors is an integer number (1062695319840).

Almost surely, 2^{12133343614540} is an apocalyptic number.

12133343614540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12133343614540 is an abundant number, since it is smaller than the sum of its proper divisors (13371344061620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12133343614540 is a wasteful number, since it uses less digits than its factorization.

12133343614540 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 587287761 (or 587287759 counting only the distinct ones).

The product of its (nonzero) digits is 311040, while the sum is 40.

Adding to 12133343614540 its reverse (4541634333121), we get a palindrome (16674977947661).

The spelling of 12133343614540 in words is "twelve trillion, one hundred thirty-three billion, three hundred forty-three million, six hundred fourteen thousand, five hundred forty".