Base | Representation |
---|---|
bin | 10001101010000000110… |
… | …010010000100110001101 |
3 | 11021222211211222021222212 |
4 | 101222000302100212031 |
5 | 124334410401430201 |
6 | 2325222405520205 |
7 | 153442506016541 |
oct | 21520062204615 |
9 | 4258754867885 |
10 | 1213341436301 |
11 | 428636677705 |
12 | 1771a1713065 |
13 | 8a557634a07 |
14 | 42a24371a21 |
15 | 218660d3abb |
hex | 11a80c9098d |
1213341436301 has 4 divisors (see below), whose sum is σ = 1213415604192. Its totient is φ = 1213267268412.
The previous prime is 1213341436277. The next prime is 1213341436309. The reversal of 1213341436301 is 1036341433121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1213341436301 - 226 = 1213274327437 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1213341436309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37059401 + ... + 37092126.
It is an arithmetic number, because the mean of its divisors is an integer number (303353901048).
Almost surely, 21213341436301 is an apocalyptic number.
It is an amenable number.
1213341436301 is a deficient number, since it is larger than the sum of its proper divisors (74167891).
1213341436301 is an equidigital number, since it uses as much as digits as its factorization.
1213341436301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74167890.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 1213341436301 its reverse (1036341433121), we get a palindrome (2249682869422).
The spelling of 1213341436301 in words is "one trillion, two hundred thirteen billion, three hundred forty-one million, four hundred thirty-six thousand, three hundred one".
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