1213342113431 has 4 divisors (see below), whose sum is σ = 1386676701072. Its totient is φ = 1040007525792.

The previous prime is 1213342113421. The next prime is 1213342113481. The reversal of 1213342113431 is 1343112433121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1213342113431 - 2¹⁰ = 1213342112407 is a prime.

It is a super-2 number, since 2×1213342113431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1213342113394 and 1213342113403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213342113421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86667293810 + ... + 86667293823.

It is an arithmetic number, because the mean of its divisors is an integer number (346669175268).

Almost surely, 2^{1213342113431} is an apocalyptic number.

1213342113431 is a deficient number, since it is larger than the sum of its proper divisors (173334587641).

1213342113431 is an equidigital number, since it uses as much as digits as its factorization.

1213342113431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 173334587640.

The product of its digits is 5184, while the sum is 29.

Adding to 1213342113431 its reverse (1343112433121), we get a palindrome (2556454546552).

The spelling of 1213342113431 in words is "one trillion, two hundred thirteen billion, three hundred forty-two million, one hundred thirteen thousand, four hundred thirty-one".