1213404413537 has 2 divisors, whose sum is σ = 1213404413538. Its totient is φ = 1213404413536.

The previous prime is 1213404413483. The next prime is 1213404413539. The reversal of 1213404413537 is 7353144043121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1060084396816 + 153320016721 = 1029604^2 + 391561^2 .

It is an emirp because it is prime and its reverse (7353144043121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1213404413537 is a prime.

Together with 1213404413539, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1213404413537.

It is not a weakly prime, because it can be changed into another prime (1213404413539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606702206768 + 606702206769.

It is an arithmetic number, because the mean of its divisors is an integer number (606702206769).

Almost surely, 2^{1213404413537} is an apocalyptic number.

It is an amenable number.

1213404413537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213404413537 is an equidigital number, since it uses as much as digits as its factorization.

1213404413537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 38.

Adding to 1213404413537 its reverse (7353144043121), we get a palindrome (8566548456658).

The spelling of 1213404413537 in words is "one trillion, two hundred thirteen billion, four hundred four million, four hundred thirteen thousand, five hundred thirty-seven".