Base | Representation |
---|---|
bin | 10001101010000100100… |
… | …100101111001000110011 |
3 | 11022000000021120200022221 |
4 | 101222010210233020303 |
5 | 124340023140001433 |
6 | 2325233000141511 |
7 | 153444210216262 |
oct | 21520444571063 |
9 | 4260007520287 |
10 | 1213405000243 |
11 | 428669542197 |
12 | 1771baa67897 |
13 | 8a56785bc07 |
14 | 42a2c99a5d9 |
15 | 2186b98c72d |
hex | 11a8492f233 |
1213405000243 has 12 divisors (see below), whose sum is σ = 1268519188048. Its totient is φ = 1160589996720.
The previous prime is 1213405000231. The next prime is 1213405000253. The reversal of 1213405000243 is 3420005043121.
It is a de Polignac number, because none of the positive numbers 2k-1213405000243 is a prime.
It is a super-2 number, since 2×12134050002432 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1213405000253) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 13508746 + ... + 13598272.
Almost surely, 21213405000243 is an apocalyptic number.
1213405000243 is a deficient number, since it is larger than the sum of its proper divisors (55114187805).
1213405000243 is an equidigital number, since it uses as much as digits as its factorization.
1213405000243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115194 (or 115171 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
The spelling of 1213405000243 in words is "one trillion, two hundred thirteen billion, four hundred five million, two hundred forty-three", and thus it is an aban number.
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