121341102334042 has 4 divisors (see below), whose sum is σ = 182011653501066. Its totient is φ = 60670551167020.

The previous prime is 121341102334031. The next prime is 121341102334087. The reversal of 121341102334042 is 240433201143121.

It is a happy number.

121341102334042 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 108548455358281 + 12792646975761 = 10418659^2 + 3576681^2 .

It is a junction number, because it is equal to n+sod(n) for n = 121341102333995 and 121341102334013.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30335275583509 + ... + 30335275583512.

Almost surely, 2^{121341102334042} is an apocalyptic number.

121341102334042 is a deficient number, since it is larger than the sum of its proper divisors (60670551167024).

121341102334042 is an equidigital number, since it uses as much as digits as its factorization.

121341102334042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60670551167023.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 121341102334042 its reverse (240433201143121), we get a palindrome (361774303477163).

The spelling of 121341102334042 in words is "one hundred twenty-one trillion, three hundred forty-one billion, one hundred two million, three hundred thirty-four thousand, forty-two".