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1213411114957 is a prime number
BaseRepresentation
bin10001101010000100111…
…100000011111111001101
311022000000201002100010211
4101222010330003333031
5124340031221134312
62325233335202421
7153444313204366
oct21520474037715
94260021070124
101213411114957
11428671a39278
12177200b16411
138a568bc01a2
1442a2d70cb6d
152186c2993a7
hex11a84f03fcd

1213411114957 has 2 divisors, whose sum is σ = 1213411114958. Its totient is φ = 1213411114956.

The previous prime is 1213411114943. The next prime is 1213411114973. The reversal of 1213411114957 is 7594111143121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1202062260996 + 11348853961 = 1096386^2 + 106531^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213411114957 - 227 = 1213276897229 is a prime.

It is a super-2 number, since 2×12134111149572 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213411114997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606705557478 + 606705557479.

It is an arithmetic number, because the mean of its divisors is an integer number (606705557479).

Almost surely, 21213411114957 is an apocalyptic number.

It is an amenable number.

1213411114957 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213411114957 is an equidigital number, since it uses as much as digits as its factorization.

1213411114957 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 30240, while the sum is 40.

The spelling of 1213411114957 in words is "one trillion, two hundred thirteen billion, four hundred eleven million, one hundred fourteen thousand, nine hundred fifty-seven".