Base | Representation |
---|---|
bin | 10001101010000101000… |
… | …001100000010000111111 |
3 | 11022000000210202210222212 |
4 | 101222011001200100333 |
5 | 124340032102312003 |
6 | 2325233425531035 |
7 | 153444331265411 |
oct | 21520501402077 |
9 | 4260023683885 |
10 | 1213412541503 |
11 | 428672823038 |
12 | 1772014a3a7b |
13 | 8a56929c5b6 |
14 | 42a2d9a09b1 |
15 | 2186c47bdd8 |
hex | 11a8506043f |
1213412541503 has 2 divisors, whose sum is σ = 1213412541504. Its totient is φ = 1213412541502.
The previous prime is 1213412541493. The next prime is 1213412541541. The reversal of 1213412541503 is 3051452143121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1213412541503 - 28 = 1213412541247 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1213412541503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1213412541553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606706270751 + 606706270752.
It is an arithmetic number, because the mean of its divisors is an integer number (606706270752).
Almost surely, 21213412541503 is an apocalyptic number.
1213412541503 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213412541503 is an equidigital number, since it uses as much as digits as its factorization.
1213412541503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 1213412541503 its reverse (3051452143121), we get a palindrome (4264864684624).
The spelling of 1213412541503 in words is "one trillion, two hundred thirteen billion, four hundred twelve million, five hundred forty-one thousand, five hundred three".
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