Base | Representation |
---|---|
bin | 10001101010000101011… |
… | …110011100111011111011 |
3 | 11022000001100001100111220 |
4 | 101222011132130323323 |
5 | 124340041023130133 |
6 | 2325234300323123 |
7 | 153444452632422 |
oct | 21520536347373 |
9 | 4260040040456 |
10 | 1213420130043 |
11 | 428677036460 |
12 | 177203b434a3 |
13 | 8a56aa28664 |
14 | 42a309b82b9 |
15 | 2186ce7a5b3 |
hex | 11a8579cefb |
1213420130043 has 16 divisors (see below), whose sum is σ = 1775176909056. Its totient is φ = 731155233440.
The previous prime is 1213420130023. The next prime is 1213420130047. The reversal of 1213420130043 is 3400310243121.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1213420130043 - 212 = 1213420125947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1213420129995 and 1213420130022.
It is not an unprimeable number, because it can be changed into a prime (1213420130047) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 106266855 + ... + 106278272.
It is an arithmetic number, because the mean of its divisors is an integer number (110948556816).
Almost surely, 21213420130043 is an apocalyptic number.
1213420130043 is a deficient number, since it is larger than the sum of its proper divisors (561756779013).
1213420130043 is a wasteful number, since it uses less digits than its factorization.
1213420130043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 212545314.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 1213420130043 its reverse (3400310243121), we get a palindrome (4613730373164).
The spelling of 1213420130043 in words is "one trillion, two hundred thirteen billion, four hundred twenty million, one hundred thirty thousand, forty-three".
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