Base | Representation |
---|---|
bin | 10001101010000101101… |
… | …011001111110101101011 |
3 | 11022000001120100202122102 |
4 | 101222011223033311223 |
5 | 124340042402444032 |
6 | 2325234500244015 |
7 | 153444523302461 |
oct | 21520553176553 |
9 | 4260046322572 |
10 | 1213423484267 |
11 | 428678a17545 |
12 | 1772050a060b |
13 | 8a56b6312c7 |
14 | 42a3120c831 |
15 | 2186d3de362 |
hex | 11a85acfd6b |
1213423484267 has 4 divisors (see below), whose sum is σ = 1213428766056. Its totient is φ = 1213418202480.
The previous prime is 1213423484249. The next prime is 1213423484279. The reversal of 1213423484267 is 7624843243121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1213423484267 - 216 = 1213423418731 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1213423484467) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2279834 + ... + 2761247.
It is an arithmetic number, because the mean of its divisors is an integer number (303357191514).
Almost surely, 21213423484267 is an apocalyptic number.
1213423484267 is a deficient number, since it is larger than the sum of its proper divisors (5281789).
1213423484267 is an equidigital number, since it uses as much as digits as its factorization.
1213423484267 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5281788.
The product of its digits is 1548288, while the sum is 47.
The spelling of 1213423484267 in words is "one trillion, two hundred thirteen billion, four hundred twenty-three million, four hundred eighty-four thousand, two hundred sixty-seven".
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