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1213423614147 = 3404474538049
BaseRepresentation
bin10001101010000101101…
…011101111100011000011
311022000001120121100210210
4101222011223233203003
5124340042421123042
62325234503125203
7153444524353233
oct21520553574303
94260046540723
101213423614147
11428678aa6088
12177205143803
138a56b678464
1442a31243cc3
152186d417a9c
hex11a85aef8c3

1213423614147 has 4 divisors (see below), whose sum is σ = 1617898152200. Its totient is φ = 808949076096.

The previous prime is 1213423614127. The next prime is 1213423614173. The reversal of 1213423614147 is 7414163243121.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1213423614147 - 27 = 1213423614019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1213423614127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202237269022 + ... + 202237269027.

It is an arithmetic number, because the mean of its divisors is an integer number (404474538050).

Almost surely, 21213423614147 is an apocalyptic number.

1213423614147 is a deficient number, since it is larger than the sum of its proper divisors (404474538053).

1213423614147 is an equidigital number, since it uses as much as digits as its factorization.

1213423614147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 404474538052.

The product of its digits is 96768, while the sum is 39.

Adding to 1213423614147 its reverse (7414163243121), we get a palindrome (8627586857268).

The spelling of 1213423614147 in words is "one trillion, two hundred thirteen billion, four hundred twenty-three million, six hundred fourteen thousand, one hundred forty-seven".

Divisors: 1 3 404474538049 1213423614147