Base | Representation |
---|---|
bin | 10001101010000101101… |
… | …011101111100010101111 |
3 | 11022000001120121100210001 |
4 | 101222011223233202233 |
5 | 124340042421123002 |
6 | 2325234503125131 |
7 | 153444524353204 |
oct | 21520553574257 |
9 | 4260046540701 |
10 | 1213423614127 |
11 | 428678aa606a |
12 | 1772051437a7 |
13 | 8a56b67844a |
14 | 42a31243cab |
15 | 2186d417a87 |
hex | 11a85aef8af |
1213423614127 has 2 divisors, whose sum is σ = 1213423614128. Its totient is φ = 1213423614126.
The previous prime is 1213423614121. The next prime is 1213423614173. The reversal of 1213423614127 is 7214163243121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1213423614127 - 23 = 1213423614119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1213423614121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606711807063 + 606711807064.
It is an arithmetic number, because the mean of its divisors is an integer number (606711807064).
Almost surely, 21213423614127 is an apocalyptic number.
1213423614127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213423614127 is an equidigital number, since it uses as much as digits as its factorization.
1213423614127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48384, while the sum is 37.
Adding to 1213423614127 its reverse (7214163243121), we get a palindrome (8427586857248).
The spelling of 1213423614127 in words is "one trillion, two hundred thirteen billion, four hundred twenty-three million, six hundred fourteen thousand, one hundred twenty-seven".
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