Search a number
-
+
121343201435 = 557142501997
BaseRepresentation
bin111000100000010011…
…1100101000010011011
3102121012121122022110202
41301000213211002123
53442002324421220
6131424433532415
711523666123401
oct1610047450233
9377177568422
10121343201435
114750908a255
121b62571410b
13b59a56a111
145c318b1471
153252d7b275
hex1c409e509b

121343201435 has 8 divisors (see below), whose sum is σ = 145866857136. Its totient is φ = 96904550880.

The previous prime is 121343201351. The next prime is 121343201437. The reversal of 121343201435 is 534102343121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 121343201435 - 220 = 121342152859 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121343201398 and 121343201407.

It is not an unprimeable number, because it can be changed into a prime (121343201437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21248144 + ... + 21253853.

It is an arithmetic number, because the mean of its divisors is an integer number (18233357142).

Almost surely, 2121343201435 is an apocalyptic number.

121343201435 is a deficient number, since it is larger than the sum of its proper divisors (24523655701).

121343201435 is an equidigital number, since it uses as much as digits as its factorization.

121343201435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42502573.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 121343201435 its reverse (534102343121), we get a palindrome (655445544556).

The spelling of 121343201435 in words is "one hundred twenty-one billion, three hundred forty-three million, two hundred one thousand, four hundred thirty-five".

Divisors: 1 5 571 2855 42501997 212509985 24268640287 121343201435