Base | Representation |
---|---|
bin | 10001101010000110001… |
… | …011111011111010111111 |
3 | 11022000002011111010100011 |
4 | 101222012023323322333 |
5 | 124340102101202224 |
6 | 2325235404044051 |
7 | 153444656162464 |
oct | 21520613737277 |
9 | 4260064433304 |
10 | 1213432053439 |
11 | 42868283a701 |
12 | 177207b33627 |
13 | 8a570341818 |
14 | 42a323dd66b |
15 | 2186e033394 |
hex | 11a862fbebf |
1213432053439 has 2 divisors, whose sum is σ = 1213432053440. Its totient is φ = 1213432053438.
The previous prime is 1213432053419. The next prime is 1213432053553. The reversal of 1213432053439 is 9343502343121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1213432053439 - 213 = 1213432045247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1213432053409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606716026719 + 606716026720.
It is an arithmetic number, because the mean of its divisors is an integer number (606716026720).
Almost surely, 21213432053439 is an apocalyptic number.
1213432053439 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213432053439 is an equidigital number, since it uses as much as digits as its factorization.
1213432053439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 40.
The spelling of 1213432053439 in words is "one trillion, two hundred thirteen billion, four hundred thirty-two million, fifty-three thousand, four hundred thirty-nine".
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