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1213433101949 is a prime number
BaseRepresentation
bin10001101010000110001…
…111111011111001111101
311022000002020110101121212
4101222012033323321331
5124340102333230244
62325235442334205
7153445001120405
oct21520617737175
94260066411555
101213433101949
11428683396442
1217720835a365
138a57061ab43
1442a325d3805
152186e18dd9e
hex11a863fbe7d

1213433101949 has 2 divisors, whose sum is σ = 1213433101950. Its totient is φ = 1213433101948.

The previous prime is 1213433101817. The next prime is 1213433102023. The reversal of 1213433101949 is 9491013343121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1202432868025 + 11000233924 = 1096555^2 + 104882^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1213433101949 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213433107949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606716550974 + 606716550975.

It is an arithmetic number, because the mean of its divisors is an integer number (606716550975).

Almost surely, 21213433101949 is an apocalyptic number.

It is an amenable number.

1213433101949 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213433101949 is an equidigital number, since it uses as much as digits as its factorization.

1213433101949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 1213433101949 in words is "one trillion, two hundred thirteen billion, four hundred thirty-three million, one hundred one thousand, nine hundred forty-nine".