1213443331 has 4 divisors (see below), whose sum is σ = 1213524592. Its totient is φ = 1213362072.

The previous prime is 1213443311. The next prime is 1213443337. The reversal of 1213443331 is 1333443121.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1213443331 - 2⁵ = 1213443299 is a prime.

It is a super-2 number, since 2×1213443331² = 2944889435096751122, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1213443296 and 1213443305.

It is not an unprimeable number, because it can be changed into a prime (1213443337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11055 + ... + 50488.

It is an arithmetic number, because the mean of its divisors is an integer number (303381148).

Almost surely, 2^1213443331 is an apocalyptic number.

1213443331 is a deficient number, since it is larger than the sum of its proper divisors (81261).

1213443331 is an equidigital number, since it uses as much as digits as its factorization.

1213443331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81260.

The product of its digits is 2592, while the sum is 25.

The square root of 1213443331 is about 34834.5135031336. The cubic root of 1213443331 is about 1066.6120841970.

Adding to 1213443331 its reverse (1333443121), we get a palindrome (2546886452).

The spelling of 1213443331 in words is "one billion, two hundred thirteen million, four hundred forty-three thousand, three hundred thirty-one".