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1213450220054 = 21777341432251
BaseRepresentation
bin10001101010000111010…
…001001111001000010110
311022000010102200002020202
4101222013101033020112
5124340121224020204
62325241253300502
7153445266454412
oct21520721171026
94260112602222
101213450220054
11428692018536
12177212034732
138a5740325b7
1442a349abd42
1521870920e1e
hex11a8744f216

1213450220054 has 8 divisors (see below), whose sum is σ = 1821199632168. Its totient is φ = 606383676000.

The previous prime is 1213450220029. The next prime is 1213450220077. The reversal of 1213450220054 is 4500220543121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×12134502200542 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1213450219999 and 1213450220026.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 170712572 + ... + 170719679.

It is an arithmetic number, because the mean of its divisors is an integer number (227649954021).

Almost surely, 21213450220054 is an apocalyptic number.

1213450220054 is a deficient number, since it is larger than the sum of its proper divisors (607749412114).

1213450220054 is a wasteful number, since it uses less digits than its factorization.

1213450220054 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 341434030.

The product of its (nonzero) digits is 9600, while the sum is 29.

Adding to 1213450220054 its reverse (4500220543121), we get a palindrome (5713670763175).

The spelling of 1213450220054 in words is "one trillion, two hundred thirteen billion, four hundred fifty million, two hundred twenty thousand, fifty-four".

Divisors: 1 2 1777 3554 341432251 682864502 606725110027 1213450220054