1213451013132 has 24 divisors (see below), whose sum is σ = 3145984108400. Its totient is φ = 404483671008.

The previous prime is 1213451013053. The next prime is 1213451013191. The reversal of 1213451013132 is 2313101543121.

1213451013132 is a `hidden beast` number, since 1 + 2 + 1 + 3 + 4 + 510 + 13 + 132 = 666.

It is a super-2 number, since 2×1213451013132² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1213451013096 and 1213451013105.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5617828657 + ... + 5617828872.

Almost surely, 2^{1213451013132} is an apocalyptic number.

1213451013132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1213451013132 is an abundant number, since it is smaller than the sum of its proper divisors (1932533095268).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1213451013132 is a wasteful number, since it uses less digits than its factorization.

1213451013132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11235657542 (or 11235657534 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 27.

Adding to 1213451013132 its reverse (2313101543121), we get a palindrome (3526552556253).

The spelling of 1213451013132 in words is "one trillion, two hundred thirteen billion, four hundred fifty-one million, thirteen thousand, one hundred thirty-two".